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Delta-Wye
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LibraLogic
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Mana: 
 Posted: Mon Jun 16th, 2008 05:23 pm

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 Ok...heres the basic priciples Ive gathered re: Delta-Wye Connections, and Im looking for somebody to confirm these so I can commit to memory and move on...
If connecting 1-HOT(A) and 1-HOT(B) in DY=208v; in DD 240v

[The result of 208v in the DY is due to the 3phs's. 3phs consists of 2 hot and 1 Ntrl. Since theres only 2 hot ((AT)120v ea) for a 3phs you use the sq-rt of 3= 1.73)....and in other words you take 1 hot ((AT)120v) x 1.73 which is how you can only extract 208v. from DY]

[The result of 240v in the DD is simply 2x each hot or (2 x 120v)=240v]

If connecting 1-HOT(A) and NEUTRAL(N) in DY=120v; in DD 208v-(pls verify).

Therefore in DY: available Volts are 208v(3phs), 208v (Sngl Phs), and 120v (Sngl Phs)....

Whereas in DD: available Volts are 240v (3phs), 240v (Sngl Phs), and 120v (sng Phs)

Please share your thoughts.

Far Galaxy
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Mana: 
 Posted: Tue Jun 17th, 2008 02:34 am

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god bless........I skip on this topic:Dtoo difficult for architects.
maybe I won't have it in my test, and if it will, 1 question, guess....

beerae
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Mana: 
 Posted: Tue Jun 17th, 2008 12:37 pm

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I am a little foggy on this topic as well, but I believe that 3 phase connections (both delt a wye) have three hot wires, if you desire a neutral (most of the time with wye, but rarely with delta) that actually becomes your forth wire.

LibraLogic
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Mana: 
 Posted: Tue Jun 17th, 2008 12:42 pm

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Ok, I could understand that logic, however would adding the fourth wire, (resulting in 3 hots) change any of the available voltage of the below...?

"Therefore in DY: available Volts are 208v(3phs), 208v (Sngl Phs), and 120v (Sngl Phs)....

Whereas in DD: available Volts are 240v (3phs), 240v (Sngl Phs), and 120v (sng Phs)"

beerae
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Mana: 
 Posted: Tue Jun 17th, 2008 12:44 pm

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No, I think you have the voltages right...


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